\(\int \frac {\csc (a+b x) \sec ^3(a+b x)}{c+d x} \, dx\) [314]
Optimal result
Integrand size = 22, antiderivative size = 22 \[
\int \frac {\csc (a+b x) \sec ^3(a+b x)}{c+d x} \, dx=\text {Int}\left (\frac {\csc (a+b x) \sec ^3(a+b x)}{c+d x},x\right )
\]
[Out]
CannotIntegrate(csc(b*x+a)*sec(b*x+a)^3/(d*x+c),x)
Rubi [N/A]
Not integrable
Time = 0.21 (sec) , antiderivative size = 22, normalized size of antiderivative = 1.00, number of
steps used = 0, number of rules used = 0, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.000, Rules used = {} \[
\int \frac {\csc (a+b x) \sec ^3(a+b x)}{c+d x} \, dx=\int \frac {\csc (a+b x) \sec ^3(a+b x)}{c+d x} \, dx
\]
[In]
Int[(Csc[a + b*x]*Sec[a + b*x]^3)/(c + d*x),x]
[Out]
Defer[Int][(Csc[a + b*x]*Sec[a + b*x]^3)/(c + d*x), x]
Rubi steps \begin{align*}
\text {integral}& = \int \frac {\csc (a+b x) \sec ^3(a+b x)}{c+d x} \, dx \\
\end{align*}
Mathematica [N/A]
Not integrable
Time = 7.90 (sec) , antiderivative size = 24, normalized size of antiderivative = 1.09
\[
\int \frac {\csc (a+b x) \sec ^3(a+b x)}{c+d x} \, dx=\int \frac {\csc (a+b x) \sec ^3(a+b x)}{c+d x} \, dx
\]
[In]
Integrate[(Csc[a + b*x]*Sec[a + b*x]^3)/(c + d*x),x]
[Out]
Integrate[(Csc[a + b*x]*Sec[a + b*x]^3)/(c + d*x), x]
Maple [N/A] (verified)
Not integrable
Time = 0.42 (sec) , antiderivative size = 22, normalized size of antiderivative = 1.00
\[\int \frac {\csc \left (x b +a \right ) \sec \left (x b +a \right )^{3}}{d x +c}d x\]
[In]
int(csc(b*x+a)*sec(b*x+a)^3/(d*x+c),x)
[Out]
int(csc(b*x+a)*sec(b*x+a)^3/(d*x+c),x)
Fricas [N/A]
Not integrable
Time = 0.33 (sec) , antiderivative size = 24, normalized size of antiderivative = 1.09
\[
\int \frac {\csc (a+b x) \sec ^3(a+b x)}{c+d x} \, dx=\int { \frac {\csc \left (b x + a\right ) \sec \left (b x + a\right )^{3}}{d x + c} \,d x }
\]
[In]
integrate(csc(b*x+a)*sec(b*x+a)^3/(d*x+c),x, algorithm="fricas")
[Out]
integral(csc(b*x + a)*sec(b*x + a)^3/(d*x + c), x)
Sympy [N/A]
Not integrable
Time = 2.52 (sec) , antiderivative size = 20, normalized size of antiderivative = 0.91
\[
\int \frac {\csc (a+b x) \sec ^3(a+b x)}{c+d x} \, dx=\int \frac {\csc {\left (a + b x \right )} \sec ^{3}{\left (a + b x \right )}}{c + d x}\, dx
\]
[In]
integrate(csc(b*x+a)*sec(b*x+a)**3/(d*x+c),x)
[Out]
Integral(csc(a + b*x)*sec(a + b*x)**3/(c + d*x), x)
Maxima [N/A]
Not integrable
Time = 1.71 (sec) , antiderivative size = 1865, normalized size of antiderivative = 84.77
\[
\int \frac {\csc (a+b x) \sec ^3(a+b x)}{c+d x} \, dx=\int { \frac {\csc \left (b x + a\right ) \sec \left (b x + a\right )^{3}}{d x + c} \,d x }
\]
[In]
integrate(csc(b*x+a)*sec(b*x+a)^3/(d*x+c),x, algorithm="maxima")
[Out]
(4*(b*d*x + b*c)*cos(2*b*x + 2*a)^2 + 4*(b*d*x + b*c)*sin(2*b*x + 2*a)^2 + (2*(b*d*x + b*c)*cos(2*b*x + 2*a) -
d*sin(2*b*x + 2*a))*cos(4*b*x + 4*a) + 2*(b*d*x + b*c)*cos(2*b*x + 2*a) + (b^2*d^2*x^2 + 2*b^2*c*d*x + b^2*c^
2 + (b^2*d^2*x^2 + 2*b^2*c*d*x + b^2*c^2)*cos(4*b*x + 4*a)^2 + 4*(b^2*d^2*x^2 + 2*b^2*c*d*x + b^2*c^2)*cos(2*b
*x + 2*a)^2 + (b^2*d^2*x^2 + 2*b^2*c*d*x + b^2*c^2)*sin(4*b*x + 4*a)^2 + 4*(b^2*d^2*x^2 + 2*b^2*c*d*x + b^2*c^
2)*sin(4*b*x + 4*a)*sin(2*b*x + 2*a) + 4*(b^2*d^2*x^2 + 2*b^2*c*d*x + b^2*c^2)*sin(2*b*x + 2*a)^2 + 2*(b^2*d^2
*x^2 + 2*b^2*c*d*x + b^2*c^2 + 2*(b^2*d^2*x^2 + 2*b^2*c*d*x + b^2*c^2)*cos(2*b*x + 2*a))*cos(4*b*x + 4*a) + 4*
(b^2*d^2*x^2 + 2*b^2*c*d*x + b^2*c^2)*cos(2*b*x + 2*a))*integrate(2*(b^2*d^2*x^2 + 2*b^2*c*d*x + b^2*c^2 + d^2
)*sin(2*b*x + 2*a)/(b^2*d^3*x^3 + 3*b^2*c*d^2*x^2 + 3*b^2*c^2*d*x + b^2*c^3 + (b^2*d^3*x^3 + 3*b^2*c*d^2*x^2 +
3*b^2*c^2*d*x + b^2*c^3)*cos(2*b*x + 2*a)^2 + (b^2*d^3*x^3 + 3*b^2*c*d^2*x^2 + 3*b^2*c^2*d*x + b^2*c^3)*sin(2
*b*x + 2*a)^2 + 2*(b^2*d^3*x^3 + 3*b^2*c*d^2*x^2 + 3*b^2*c^2*d*x + b^2*c^3)*cos(2*b*x + 2*a)), x) - (b^2*d^2*x
^2 + 2*b^2*c*d*x + b^2*c^2 + (b^2*d^2*x^2 + 2*b^2*c*d*x + b^2*c^2)*cos(4*b*x + 4*a)^2 + 4*(b^2*d^2*x^2 + 2*b^2
*c*d*x + b^2*c^2)*cos(2*b*x + 2*a)^2 + (b^2*d^2*x^2 + 2*b^2*c*d*x + b^2*c^2)*sin(4*b*x + 4*a)^2 + 4*(b^2*d^2*x
^2 + 2*b^2*c*d*x + b^2*c^2)*sin(4*b*x + 4*a)*sin(2*b*x + 2*a) + 4*(b^2*d^2*x^2 + 2*b^2*c*d*x + b^2*c^2)*sin(2*
b*x + 2*a)^2 + 2*(b^2*d^2*x^2 + 2*b^2*c*d*x + b^2*c^2 + 2*(b^2*d^2*x^2 + 2*b^2*c*d*x + b^2*c^2)*cos(2*b*x + 2*
a))*cos(4*b*x + 4*a) + 4*(b^2*d^2*x^2 + 2*b^2*c*d*x + b^2*c^2)*cos(2*b*x + 2*a))*integrate(sin(b*x + a)/((d*x
+ c)*cos(b*x + a)^2 + (d*x + c)*sin(b*x + a)^2 + d*x + 2*(d*x + c)*cos(b*x + a) + c), x) + (b^2*d^2*x^2 + 2*b^
2*c*d*x + b^2*c^2 + (b^2*d^2*x^2 + 2*b^2*c*d*x + b^2*c^2)*cos(4*b*x + 4*a)^2 + 4*(b^2*d^2*x^2 + 2*b^2*c*d*x +
b^2*c^2)*cos(2*b*x + 2*a)^2 + (b^2*d^2*x^2 + 2*b^2*c*d*x + b^2*c^2)*sin(4*b*x + 4*a)^2 + 4*(b^2*d^2*x^2 + 2*b^
2*c*d*x + b^2*c^2)*sin(4*b*x + 4*a)*sin(2*b*x + 2*a) + 4*(b^2*d^2*x^2 + 2*b^2*c*d*x + b^2*c^2)*sin(2*b*x + 2*a
)^2 + 2*(b^2*d^2*x^2 + 2*b^2*c*d*x + b^2*c^2 + 2*(b^2*d^2*x^2 + 2*b^2*c*d*x + b^2*c^2)*cos(2*b*x + 2*a))*cos(4
*b*x + 4*a) + 4*(b^2*d^2*x^2 + 2*b^2*c*d*x + b^2*c^2)*cos(2*b*x + 2*a))*integrate(sin(b*x + a)/((d*x + c)*cos(
b*x + a)^2 + (d*x + c)*sin(b*x + a)^2 + d*x - 2*(d*x + c)*cos(b*x + a) + c), x) + (d*cos(2*b*x + 2*a) + 2*(b*d
*x + b*c)*sin(2*b*x + 2*a) + d)*sin(4*b*x + 4*a) + d*sin(2*b*x + 2*a))/(b^2*d^2*x^2 + 2*b^2*c*d*x + b^2*c^2 +
(b^2*d^2*x^2 + 2*b^2*c*d*x + b^2*c^2)*cos(4*b*x + 4*a)^2 + 4*(b^2*d^2*x^2 + 2*b^2*c*d*x + b^2*c^2)*cos(2*b*x +
2*a)^2 + (b^2*d^2*x^2 + 2*b^2*c*d*x + b^2*c^2)*sin(4*b*x + 4*a)^2 + 4*(b^2*d^2*x^2 + 2*b^2*c*d*x + b^2*c^2)*s
in(4*b*x + 4*a)*sin(2*b*x + 2*a) + 4*(b^2*d^2*x^2 + 2*b^2*c*d*x + b^2*c^2)*sin(2*b*x + 2*a)^2 + 2*(b^2*d^2*x^2
+ 2*b^2*c*d*x + b^2*c^2 + 2*(b^2*d^2*x^2 + 2*b^2*c*d*x + b^2*c^2)*cos(2*b*x + 2*a))*cos(4*b*x + 4*a) + 4*(b^2
*d^2*x^2 + 2*b^2*c*d*x + b^2*c^2)*cos(2*b*x + 2*a))
Giac [N/A]
Not integrable
Time = 0.68 (sec) , antiderivative size = 24, normalized size of antiderivative = 1.09
\[
\int \frac {\csc (a+b x) \sec ^3(a+b x)}{c+d x} \, dx=\int { \frac {\csc \left (b x + a\right ) \sec \left (b x + a\right )^{3}}{d x + c} \,d x }
\]
[In]
integrate(csc(b*x+a)*sec(b*x+a)^3/(d*x+c),x, algorithm="giac")
[Out]
integrate(csc(b*x + a)*sec(b*x + a)^3/(d*x + c), x)
Mupad [N/A]
Not integrable
Time = 25.31 (sec) , antiderivative size = 26, normalized size of antiderivative = 1.18
\[
\int \frac {\csc (a+b x) \sec ^3(a+b x)}{c+d x} \, dx=\int \frac {1}{{\cos \left (a+b\,x\right )}^3\,\sin \left (a+b\,x\right )\,\left (c+d\,x\right )} \,d x
\]
[In]
int(1/(cos(a + b*x)^3*sin(a + b*x)*(c + d*x)),x)
[Out]
int(1/(cos(a + b*x)^3*sin(a + b*x)*(c + d*x)), x)